Class 11 · Notes

Rotational Motion— Notes, Formulas & Revision

Complete revision notes and formulas for Rotational Motion (Class 11). Curated for JEE, NEET, AP Physics, SAT, and CUET. Tap any topic to open the live simulation and full PYQ set.

Angular Kinematics

ω = ω₀ + αt, θ = ω₀t + ½αt² — see disk spin with live ω(t) and θ(t) plots.

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Angular kinematics describes rotation: θ (angle), ω (angular velocity), α (angular acceleration).

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Same form as linear kinematics with substitutions: x → θ, v → ω, a → α.

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Units: θ (rad), ω (rad/s), α (rad/s²). 1 rev = 2π rad = 360°.

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For uniform angular acceleration: ω = ω₀ + αt; θ = ω₀t + ½αt²; ω² = ω₀² + 2αθ.

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Linear-angular relations (for rigid body, distance r from axis): v = rω, a_tangential = rα, a_centripetal = rω² = v²/r.

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Total acceleration of a point in circular motion: a = √(a_t² + a_c²).

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Sign convention: counter-clockwise positive (by right-hand rule, ω points along rotation axis).

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Used in: rotating machinery, wheels, planets, gyroscopes.

Angular velocity

Rate of change of angular position.

Angular acceleration

Rate of change of ω.

Constant α kinematics

Direct analog of v = u + at.

Linear-angular link

Tangential vs centripetal acceleration.

Angular kinematics is structurally identical to linear — just replace symbols.

ω in rad/s, NOT rpm or rev/s. Convert: ω(rad/s) = 2π × rev/s = (π/30) × rpm.

All points of a rigid body share the SAME ω and α; their linear v and a differ by their distance r from axis.

Centripetal acceleration always exists in circular motion (a_c = rω²). Tangential acceleration only if α ≠ 0.

Direction of ω is along the rotation axis (right-hand rule).

Period T = 2π/ω. Frequency f = ω/(2π) = 1/T.

Moment of Inertia

I formulas for 6 common shapes — solid/hollow sphere, cylinder, rod.

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Moment of inertia I is the rotational analog of mass — measures resistance to angular acceleration.

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For a point mass at distance r from axis: I = mr².

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For a collection of particles: I = Σ m_i r_i². For continuous bodies: I = ∫r²·dm.

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I depends on (i) mass distribution, (ii) chosen rotation AXIS — different axes give different I.

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Common bodies (about symmetry axes): rod (about center, length L): ML²/12. Disk (about center): MR²/2. Solid sphere: 2MR²/5. Hollow sphere: 2MR²/3. Cylinder (about axis): MR²/2. Ring: MR².

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Newton's 2nd law for rotation: τ = Iα.

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Rotational KE: K = ½Iω². Higher I ⇒ more KE for same ω.

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Engineering: flywheels store rotational energy via large I.

Point mass

r = perpendicular distance from rotation axis.

Discrete system

Sum over all particles.

Continuous body

Integral form for extended objects.

Common bodies (about symmetry axis)

Standard values worth memorising.

Rotational Newton's 2nd law

Direct analog of F = ma.

I depends on AXIS — not just mass. Same body, different axis ⇒ different I.

I is larger when mass is far from axis (r² weighting).

I for a ring (all mass at R) is double that of a disk (mass spread): both = MR² but disk = ½MR² because mass is closer in.

Flywheels: heavy and large radius ⇒ high I ⇒ stores lots of rotational KE.

I for a non-symmetric body about an arbitrary axis: use inertia tensor (advanced — not in NCERT).

Common mistake: using I = MR² for a disk (it's for a ring). Disks: I = ½MR².

Torque

τ = r × F = rF sinθ — drag angle and watch rotation direction flip.

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Torque τ is the rotational analog of force — measures the tendency of a force to rotate a body about an axis.

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τ = r × F. Magnitude: τ = r·F·sin θ = F·r_perp = r·F_perp.

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Units: N·m (same as energy units, but conceptually different — vector vs scalar).

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Direction: perpendicular to plane of r and F (right-hand rule).

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Rotational Newton's 2nd law: τ_net = I·α.

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Equilibrium: a body is in mechanical equilibrium when Σ F = 0 AND Σ τ = 0 (both translational and rotational).

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Couple: two equal-magnitude, opposite-direction forces with different lines of action — produces pure rotation (net F = 0 but τ ≠ 0).

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Lever, wrench, door hinge — all use torque. Long lever arm = more rotational effect for same force.

Torque (vector)

Cross product.

Magnitude

θ = angle between r and F. Max when θ = 90°.

Newton's 2nd (rotation)

τ and α both about the SAME axis.

Equilibrium conditions

Both must hold simultaneously.

Couple moment

d = perpendicular distance between the two lines of action.

Torque has units N·m but is NOT energy — it's a vector quantity.

Maximum torque when force is PERPENDICULAR to lever arm.

Long wrench → more torque from same hand force ⇒ easier to loosen bolts.

Static equilibrium: BOTH F-balance and τ-balance must hold.

Couple: τ depends only on the separation d between forces, not on the chosen pivot point.

Doors: handle is far from hinges (large r) ⇒ small F produces enough τ to open.

Parallel Axis Theorem

I = I_cm + Md² — shift the axis and see I grow quadratically with d.

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Parallel-axis theorem: I about any parallel axis = I_CM + M·d², where I_CM is the moment of inertia about the parallel axis through the center of mass, and d is the distance between the two axes.

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Lets you find I about any axis if you know I_CM.

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I about COM is always MINIMUM (parallel-axis adds a positive term).

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Perpendicular-axis theorem (for PLANAR bodies only): I_z = I_x + I_y, where x, y are in the plane and z is perpendicular.

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Used together: parallel + perpendicular axis theorems let you compute I for many standard shapes.

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Example: rod about end: I_end = I_CM + M·(L/2)² = ML²/12 + ML²/4 = ML²/3.

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Example: disk about edge: I_edge = ½MR² + MR² = (3/2)MR².

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Theorem is universal — applies to any rigid body.

Parallel-axis theorem

d = perpendicular distance between the two axes.

Perpendicular-axis (planar)

Only for FLAT 2D bodies; z perpendicular to plane.

Rod about end

Useful in compound pendulum.

Disk about edge

Standard result.

I about ANY axis ≥ I about parallel axis through COM. Minimum I is always at the COM.

Parallel-axis adds M·d² — grows quadratically with axis separation.

Perpendicular-axis theorem is for 2D (planar) bodies only — wouldn't apply to a 3D solid like a sphere.

Combining both theorems lets you find I for many compound configurations.

Always check the I_CM value: for a thin rod about its center I = ML²/12, but about its end (using parallel-axis) it becomes ML²/3.

For a thin lamina, perpendicular-axis lets you derive I about axis perpendicular to the plane from I about two perpendicular axes in the plane.

Rotational Kinetic Energy

KE_rot = ½Iω² — compare with translational KE for rolling objects.

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Rotational kinetic energy: K_rot = ½Iω². Direct analog of K_trans = ½mv².

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Total KE of a rolling body = K_trans + K_rot = ½Mv² + ½Iω². With v = rω (rolling condition).

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For a rolling solid sphere: K_total = ½Mv² + ½·(2MR²/5)·(v/R)² = (7/10)Mv². So 71% translation, 29% rotation.

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Disk rolling: K_total = (3/4)Mv². Hollow sphere: (5/6)Mv². Ring: Mv² (50/50 split).

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Energy stored in a flywheel: K = ½Iω². Large I and large ω ⇒ huge storage. Used in regenerative braking.

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Work done by torque: W = ∫τ·dθ = ΔK_rot.

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Power delivered to rotating body: P = τ·ω.

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Rotation kinetic energy is real KE — has the same units (J) and converts to/from translational KE in rolling.

Rotational KE

Direct analog of ½mv².

Total KE (rolling)

Substitute v = ωR for rolling without slipping.

Work-energy (rotation)

Torque does work; changes K_rot.

Rotational power

Direct analog of P = Fv.

K_rot is REAL energy — comparable to and convertible with translational KE.

Rolling adds rotational KE — a rolling solid sphere has 1.4× the KE of a sliding block at same v.

Why a sliding block reaches the bottom of a ramp BEFORE a rolling sphere: rolling sphere stores energy in rotation, leaving less for translation.

Hollow vs solid: hollow ring (I = MR²) stores MORE rotational energy than solid disk (½MR²) at same ω.

Flywheel energy storage: industrial-scale flywheels can store MJ. Important for grid stability.

Common pitfall: forgetting K_rot when analyzing rolling motion.

Conservation of Angular Momentum

L = Iω conserved — pull string shorter, ω grows as (r₀/r)².

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Conservation of angular momentum: if net external TORQUE on a system is zero, total L is conserved.

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L = Iω. If I changes, ω compensates so that Iω stays constant.

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Examples: figure skater pulls in arms → I drops → ω rises. Diver tucks → spins faster.

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Holds about any FIXED axis or about the COM.

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In the absence of external torque, an isolated rotating body keeps spinning forever.

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Earth's day length is slowly INCREASING (~2.3 ms per century) because tidal friction transfers angular momentum to the Moon's orbit.

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Astronomical examples: pulsars (collapsed stars) spin extremely fast because of conservation as r shrinks during collapse.

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Conservation of L is INDEPENDENT of conservation of energy or linear momentum.

Conservation

When net external torque vanishes.

Two-state form

Before vs after a configuration change.

ω from I

Smaller I ⇒ larger ω.

KE change during arm-pull

KE INCREASES when I drops (work done by internal forces).

L is conserved when NO EXTERNAL TORQUE — internal forces (e.g., muscles) can change I but not L.

When a skater pulls in arms, KE INCREASES (despite L constant) — work done by muscles in pulling against centrifugal force.

Earth's rotation slows over geological time due to tidal torque from the Moon — angular momentum transferred to lunar orbit (Moon moves slightly farther away each year).

Conservation of L explains why galaxies, accretion disks, and protoplanetary nebulae are flat and rotating.

Common mistake: thinking ω is conserved. ω·I is conserved — separately, neither is.

Conservation of L is a DEEP symmetry: it follows from rotational invariance (Noether's theorem).

Rolling Motion

a = g sinθ/(1 + k²) — 4 shapes race down an incline; sphere wins.

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Rolling without slipping: a rotating body translates AND rotates, with v_CM = R·ω (rolling condition).

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The point of contact with the ground is INSTANTANEOUSLY AT REST.

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Total KE of a rolling body: K = ½Mv² + ½Iω². For rolling condition: K = ½Mv²(1 + I/MR²).

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Rolling friction acts at contact point — small (compared to sliding friction) because the contact area doesn't slip.

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Static friction at contact provides the torque for rolling — it does NO WORK (point of contact at rest).

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On an incline: a = g·sin θ / (1 + I/MR²). Different bodies have different accelerations.

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Solid sphere rolls fastest on an incline, hollow ball slower, then ring slowest — depends on I/MR² ratio.

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Pure rolling: no energy lost to friction. Slipping: kinetic friction acts and energy is lost.

Rolling condition

No slipping between contact and ground.

Total KE (rolling)

Combined translation + rotation.

Acceleration on incline (rolling)

Smaller for larger I/MR² (rotational inertia hogs energy).

Min coefficient of friction (rolling)

Below this μ, body slips instead of rolling.

The CONTACT POINT in pure rolling is INSTANTANEOUSLY AT REST — counterintuitive but true.

Static friction at contact point does NO WORK because the point doesn't move during instantaneous contact.

Solid sphere (I = 2MR²/5) is fastest: a = (5/7)g·sin θ. Hollow sphere (I = 2MR²/3) slower. Ring (I = MR²) slowest: a = ½g·sin θ.

Sliding (frictionless) block on incline reaches bottom first — no rotational KE to share.

If you START a solid disk rolling with too little static friction, it SLIPS — and kinetic friction takes over (acts and does work).

Rolling resistance is real but small — comes from deformation at contact, not slipping.

Linear ↔ Angular Variables

v = ωr, a_t = αr, a_c = ω²r — drag a particle on a rotating disc to see all three.

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Each particle on a rotating rigid body has linear velocity v = ωr.

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Tangential acceleration a_t = αr; centripetal a_c = ω²r = v²/r.

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Different points on the same body share ω and α, but have different v and a_c.

Linear-angular

Connects circular and rotational kinematics.

Total acceleration = √(a_t² + a_c²).

On a wheel rolling without slipping, the topmost point moves at 2v relative to ground.

Lever Balance (Torque)

Two masses on a beam — adjust weights and arms; see torque balance live.

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Lever balances when net torque about pivot is zero: m₁ g d₁ = m₂ g d₂.

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Mechanical advantage = effort arm / load arm. First-class lever has pivot in the middle.

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Most stable when COM is just above the pivot.

Balance

Torque balance about pivot.

Mechanical advantage

Force amplification.

Crowbar, scissors, seesaw — all first-class levers.

Wheelbarrow is a second-class lever (load between effort and pivot).

Radius of Gyration

k = √(I/M) — see equivalent ring radius for ring, disc, rod, sphere, shell.

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k = √(I/M) is the distance from the axis at which all the mass, if concentrated as a thin ring, would give the same I.

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Ring: k = R. Disc: k = R/√2. Solid sphere: k = R√(2/5). Hollow shell: k = R√(2/3). Rod about center: k = L/√12.

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Useful in rolling motion: a = g sinθ / (1 + k²/R²).

Definition

Equivalent ring radius.

Rolling acceleration

Smaller k/R → faster rolling.

Hollow objects have larger k than solid ones of the same mass and radius.

k depends on the chosen axis — use parallel-axis theorem if shifted.

Rolling With Slipping

Independent v and ω — detect skidding (v > ωR) vs spinning (ωR > v) vs pure rolling.

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Pure rolling: contact point is instantaneously at rest, so v = ωR.

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Skidding: v > ωR (over-braking, locked wheel sliding).

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Spinning: ωR > v (drive wheel spinning out, e.g. on ice).

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Slipping speed at contact: v_slip = v − ωR.

Pure rolling condition

Contact point at rest.

Slip velocity

Relative speed at contact.

Friction acts to oppose slip: forward friction during spinning, backward during skidding.

Once pure rolling is reached on a flat surface, friction does no work.

Gyroscopic Precession

Spinning top — see L precess about vertical at Ω = mgr/(Iω). Real animatronic feel.

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Spinning top with weight off-vertical: gravity creates torque τ perpendicular to L.

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Instead of falling, the angular momentum vector precesses around the vertical.

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Precession rate Ω = τ / L = mgr / (Iω) — slows as spin ω increases.

Precession rate

Independent of tilt for small angles.

Angular momentum

Magnitude (along spin axis).

Used in inertial navigation (gyroscopes), bicycles (stability via wheels' L), and toy tops.

Faster spin → slower precession; this is why a tossed coin doesn't tumble much.

Rotational Motion on sciphylab (also known as SciPhy, SciPhy Lab, SciPhy Labs). Free physics revision for Class 11, JEE Mains, JEE Advanced, NEET UG, AP Physics 1/2/C, SAT Subject Physics, and CUET-UG.